Updating file name
Hello all,
I have to repeat 15 times the same operation writing (different) data into .dat files. The basic name of the file is user-defined and stored in a variable, say $File. What I'd like to do is to add an extension to that file name to have something like : File1.dat, File2.dat and so on. I've tried to put all this in a FOR loop but it obviously doesn't work. Here's part of what I've done:
! for ($j=1;$j<=2;$j++) {
! $FileName= $File$j.dat;
! }
The problem seems to be in the two $ that appear there. How do you solve the problem?
Many thanks,
Felix
Re: Updating file name
created: 2006-08-04 15:05:18
Use the string concatenation operator
$FileName= $File . $j . ".dat";
or use interpolation
$FileName= "$File$j.dat";
By the way,
for (my $j=1;$j<=2;$j++)
is not nearly as readable as
for my $j (1..2)
Re: Updating file name
created: 2006-08-04 15:05:41
You can use Perl's concatenation (dot) operator to combine strings:
for(1..2) {
my $filename = $file . "$_.dat";
}
Update: s/j/_/;
Re: Updating file name
created: 2006-08-04 15:08:38
You either need to concatenate the values using '.':
$FileName= $File . $j . '.dat';Or interpolate them inside double quotes:
$FileName= "$File$j.dat";Or you can always use sprintf:
$FileName= sprintf '%s%d.dat', $File, $j;
Re: Updating file name
created: 2006-08-04 15:18:31
Many thanks.
Sometimes it's just too simple!
Re: Updating file name
created: 2006-08-05 05:21:06
Hi [F/lix],
You can get it like this,
madtoperl.
You can get it like this,
#!/bin/perl-w
use strict;
my $File = "File";
for (1..2) {
my $FileName= "$File"."$_".'.dat';
print"Filename=> $FileName\n";
}
Thanks and Regards,madtoperl.