What to these operators do?
Can someone explain or point me to what these two operators' roles are?
=~
.=
Re: What to these operators do?
created: 2006-04-03 21:40:12
You'll find the answer to this in [doc://perlop|perldoc perlop]
=~ binds a scalar expression to a pattern match, eg:
print "Matches!" if "hello" =~ m/he/;The period (.) is a concatenation operator. When used in conjunction with = it concatenates the right argument to the left argument. For example..
$foo = "hello" .= " world";Is the same as..
$foo = "hello world";
Cheers,
Darren :)
Re^2: What to these operators do?
created: 2006-04-04 01:09:04
THANK YOU!!!
Re^2: What to these operators do?
created: 2006-04-04 06:03:46
=~ can also be used in list context to obtain the list of captures: $1, $2, etc.
--
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My friends all rate Windows, I must disagree.
Your powers of persuasion will set them all free,
So oh Lord, wont you burn me a Knoppix CD ?
(Missquoting Janis Joplin)
Re^3: Explaining =~ and .= operators
created: 2006-04-04 12:02:22
Not to be overly nitpicky, but that behavior is from the m// operator, not =~. I think this distinction is important to keep in mind, because =~ can be used with m//, s/// and tr///, which all have different behaviour.